Wickedness: Yobe Housewife Allegedly Murders 3 Stepsons With Poison
A 22-year-old housewife, Khadija Yakubu, is currently cooling her feet in Police custody for allegedly killing her three stepsons through food poisoning in Yobe State.
The Yobe Police Command said one other child also affected by the poisonous substance is now lying critically ill in an undisclosed hospital.
According to the Command’s Spokesman, ASP Dungus Abdulkarim, who confirmed the arrest on Friday in Damaturu, the State capital, the incident occurred at about 9:00 am on Friday at Makarahuta in Potiskum Local Government Area of the state.
ASP Abdulkarim said preliminary investigation revealed the suspect allegedly administered a poisonous tea substance during breakfast to the children aged between seven and 12.
“The children were rushed to a hospital after taking tea prepared by the suspect in the early hours of Friday, Sept.17, at about 0900hrs. Three of the victims died while receiving treatment and one other remained unconscious”, the Command image-maker said.
He explained that the unfortunate incident was reported to the Divisional Police Headquarters, Potiskum by the suspect’s husband, Alhaji Haruna, at about 1:00 pm on the said date.
ASP Abdulkarim further said the investigation into the case was ongoing, adding that the suspect would soon be charged to court for prosecution.
